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屏蔽气体流速对同轴双管式氦气大气压等离子体射流粒子分布的影响

陈忠琪 钟安 戴栋 宁文军

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屏蔽气体流速对同轴双管式氦气大气压等离子体射流粒子分布的影响

陈忠琪, 钟安, 戴栋, 宁文军

Effect of flow rate of shielding gas on distribution of particles in coaxial double-tube helium atmospheric pressure plasma jet

Chen Zhong-Qi, Zhong An, Dai Dong, Ning Wen-Jun
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  • 在大气压等离子体射流应用中, 环境气体对射流流出物的影响不可忽视, 尤其是在某些对环境粒子高度敏感的特定场景中. 同轴双管式射流装置可用于抑制射流流出物与环境气体之间的相互扩散, 从而控制射流流出物的化学性质. 本文对同轴双管式氦气大气压等离子体射流在不同屏蔽气体流速下的放电特性和化学性质进行了数值仿真研究, 并通过实验光学图像对仿真模型加以验证. 结果表明, 相比于没有屏蔽气体的情况, 在高流速条件下放电得到增强, 而在低流速下放电较弱; 随着流速的增加, 空间中的粒子数均随之增加, 这可以归因于由屏蔽气体流速增加而产生的更宽的主放电通道. 此外, 不同浓度轮廓线上的离子径向通量受到流速的影响也存在很大差异. 本研究进一步揭示了不同的放电位置对氮氧粒子产生的影响, 加深了关于屏蔽气体流速影响等离子体射流放电行为的认识, 并可能为等离子体射流的进一步应用开辟新的机会.
    In the application of atmospheric pressure plasma jet, the influence of ambient gas cannot be ignored, especially in some specific scenarios which are highly sensitive to ambient particles. Coaxial double-tube plasma jet device is a promising method of controlling the chemical properties of jet effluent by restraining the mutual diffusion between jet effluent and ambient gas. In this work, the discharge characteristics and chemical properties of coaxial double-tube helium atmospheric pressure plasma jet at different flow rates of shielding gas are studied numerically, and the model is validated by experimental optical images. The results illustrate the enhanced discharge at the high flow rate, the weaker discharge at the low flow rate, and discharge behaviors without shielding gas as well. With the increase of shielded gas flow rate, the particle density increases in the discharge space, which can be attributed to the wider main discharge channel caused by the increase of shielding gas flow rate. In addition, the analysis shows the great difference in ion fluxes affected by the flow rate of the SG between the contour lines of different helium mole fractions. This study further reveals that different discharge positions have a great influence on the generation of nitrogen and oxygen particles, thus deepening the understanding of influence of shielding gas flow rate on discharge behavior, and may open up new opportunities for the further application of plasma jet.
      通信作者: 戴栋, ddai@scut.edu.cn
    • 基金项目: 国家自然科学基金(批准号: 51877086)资助的课题.
      Corresponding author: Dai Dong, ddai@scut.edu.cn
    • Funds: Project supported by the National Natural Science Foundation of China (Grant No. 51877086).
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  • 图 1  实验装置示意图

    Fig. 1.  Schematic diagram of experimental setup.

    图 2  仿真模型的几何结构

    Fig. 2.  The geometry of the simulation model.

    图 3  不同SG流速下的放电光学图像 (a), (c) 0 slm; (b) 1 slm; (d) 3 slm. 红色曲线表示放电时最明亮的区域

    Fig. 3.  The discharge optical images for the different SG flow rates: (a), (c) 0 slm; (b) 1 slm; (d) 3 slm. The red curve shows the brightest region of the discharge.

    图 4  (a), (c) 不同SG流速下98%氦气摩尔分数的轮廓线; (b) 氦气摩尔分数(cHe)在轴向位置z = 2.5 mm处的径向分布

    Fig. 4.  (a), (c) The contour line of the 98% helium mole fraction at different flow rates of SG; (b) the distribution of the helium mole fraction(cHe) at axial position of z = 2.5 mm.

    图 5  当SG流速处于(a) 0, (b) 1, (c) 2和(d) 3 slm情况下, 电子密度ne(单位: m–3, 以对数形式表示)的时空分布. 洋红色线分别表示不同氦气摩尔分数的等值轮廓线

    Fig. 5.  Spatial and temporal profiles of the electron density ne (unit: m–3, in 10 logarithmic scale) for SG flow rates of (a) 0, (b) 1, (c) 2 and (d) 3 slm. The magenta lines are the contour lines of different helium mole fractions.

    图 6  SG流速为(a) 0 和(b) 3 slm情况下放电空间中电离率(单位: mol·m–3·s–1, 以对数形式表示)的时空演化情况. 洋红色线分别表示不同氦气摩尔分数的等值轮廓线

    Fig. 6.  Development of the ionization rate (unit: mol·m–3·s–1, in 10 logarithmic scale) in the discharge region for SG flow rate of (a) 0 and (b) 3 slm. The magenta lines are the contour lines of different helium mole fractions.

    图 7  放电空间中(a)粒子平均数密度及(b)各粒子时间空间平均生成速率

    Fig. 7.  (a) The average species density and (b) the average spatiotemporal production rate of the species in discharge region.

    图 8  轴向位置z = 2.5 mm, He*粒子的生成速率沿径向分布

    Fig. 8.  Radial distribution of the production rate of He* at axial position z = 2.5 mm.

    图 9  不同氦气浓度轮廓线表面的离子径向通量

    Fig. 9.  Radial flux of ions on the contour lines of different helium mole fractions.

    图 10  不同氦气浓度轮廓线表面的化学反应速率

    Fig. 10.  Reaction rate on the contour lines of different helium mole fractions.

    图 11  当SG流速为(a) 0和(b) 3 slm时, 轴向位置z = 2.5 mm处的离子密度沿径向位置分布

    Fig. 11.  Distribution of ion density at axial position z = 2.5 mm for SG flow rate of (a) 0 and (b) 3 slm.

    图 12  不同氦气浓度轮廓线表面的径向电场变化情况

    Fig. 12.  Variation of the radial electric field on the contour lines of different helium mole fractions.

    图 13  $\rm N_2^+ $$\rm O_2^+ $的化学反应速率的空间分布. 洋红色线分别表示不同氦气摩尔分数的等值轮廓线

    Fig. 13.  Spatial distribution of the reaction rates involving (a) $\rm O_2^+ $ and (b) $\rm N_2^+ $. The magenta lines are the contour lines of different helium mole fractions.

    表 1  中性气体流动模型的边界条件

    Table 1.  Boundary conditions of the neutral gas flow model.

    边界表达式备注
    AX对称轴
    BCui = 3 slm, c = 1工作气体入口
    DEuo, c = 0屏蔽气体入口
    FGu = 0.1 m/s, c = 0环境空气入口
    GWp = 1 atm, ${{\boldsymbol{n}}} \cdot {D_{\text{d} } }\nabla c = 0$
    BPO, CQRD,
    UW, ESTF
    u = 0 m/s, ${{\boldsymbol{n}}} \cdot {D_{\text{d} } }\nabla c = 0$
    下载: 导出CSV

    表 2  等离子体动力学模型的边界条件

    Table 2.  Boundary conditions of the plasma dynamics model.

    边界表达式备注
    IPOV = V0, 方程(9)—方程(12)外施电压
    HX对称轴
    IJ, KL$- {\boldsymbol{n}} \cdot {\boldsymbol{D}} = 0$, $- {\boldsymbol{n} } \cdot {\boldsymbol{\varGamma} } {\text{e} } = 0$, $- {\boldsymbol{n}} \cdot {\boldsymbol{\varGamma}} {\varepsilon } = 0$
    TVV = 0, $- {\boldsymbol{n}} \cdot {\boldsymbol{\varGamma}} {\text{e} } = 0$, $- {\boldsymbol{n}} \cdot {\boldsymbol{\varGamma}} {\varepsilon } = 0$接地
    TM, XYVV = 0接地
    UV, LST, JQRK方程(9)—方程(12), 方程(14), 方程(15)
    下载: 导出CSV

    表 A  等离子体化学反应

    Table A.  Chemical reactions considered in the plasma dynamics model.

    序号反应方程式速率常数能量损耗
    /eV
    参考
    文献
    1${\rm{e+He\to e+He}}$f(c, ε) (m3·s–1)/[40]
    2${\rm{e+He\to e+He^{\ast}}}$f(c, ε) (m3·s–1)19.82[40]
    3${\rm{e+He^{\ast }\to e+He}} $f(c, ε) (m3·s–1)–19.82[40]
    4${\rm{e+He\to 2e+He^{+}}} $f(c, ε) (m3·s–1)24.587[40]
    5${\rm{e+N_{2}\to e+N_{2}}} $f(c, ε) (m3·s–1)/[40]
    6${\rm{e+N_{2}\to e+N_{2}(VIB\, \textit{v}1)}}$f(c, ε) (m3·s–1)0.2889[40]
    7${\rm{e+N_{2}\to e+N_{2}(VIB\, 3\textit{v}1)} }$f(c, ε) (m3·s–1)0.8559[40]
    8${\rm{e+N_{2}\to e+N_{2}(VIB\, 4\textit{v}1)} }$f(c, ε) (m3·s–1)1.1342[40]
    9${\rm{e+N_{2}\to e+N_{2}(VIB \,5\textit{v}1)} }$f(c, ε) (m3·s–1)1.4088[40]
    10${\rm{e+N_{2}\to 2e+N_{2}^{+}}} $f(c, ε) (m3·s–1)15.6[40]
    11${\rm{e+O_{2}\to e+O_{2}}} $f(c, ε) (m3·s–1)/[40]
    12${\rm{e+O_{2}\to O+O^{-}}} $f(c, ε) (m3·s–1)/[40]
    13${\rm{e+O_{2}\to O_{2}^{-}}} $f(c, ε) (m3·s–1)/[40]
    14${\rm{e+O_{2}\to e+O_{2}(VIB\, 3\textit{v}1)} }$f(c, ε) (m3·s–1)0.57[40]
    15${\rm{e+O_{2}\to e+O_{2}(VIB\, 4\textit{v}1)} }$f(c, ε) (m3·s–1)0.75[40]
    16${\rm{e+O_{2}\to e+O_{2} } }(\rm A1)$f(c, ε) (m3·s–1)0.997[40]
    17${\rm{e+O_{2}\to e+O_{2}}} $f(c, ε) (m3·s–1)–0.997[40]
    18${\rm{e+O_{2}\to e+O_{2} } }(\rm B1)$f(c, ε) (m3·s–1)1.627[40]
    19${\rm{e+O_{2}\to e+O_{2}}} $f(c, ε) (m3·s–1)–1.627[40]
    20${\rm{e+O_{2}\to e+O_{2}(EXC)}} $f(c, ε) (m3·s–1)4.5[40]
    21${\rm{e+O_{2}\to e+O+O}} $f(c, ε) (m3·s–1)5.58[40]
    22${\rm{e+O_{2}\to e+O+O(^{1}D)}} $f(c, ε) (m3·s–1)8.4[40]
    23${\rm{e+O_{2}\to 2e+O_{2}^{+}}}$f(c, ε)(m3·s–1)12.1[40]
    24${\rm{e+He^{\ast }\to 2e+He^{+}}} $$4.661 \times {10^{ - 16} } \times {T_{\text{e} } ^{0.6}} \times { {\rm{e} }^{ - 4.78/T_{\text{e} } } }\,({\rm m}^3{\cdot} {\rm{s} }^{-1})$4.78[41]
    25${\rm{e+He_{2}^{\ast }\to 2e+He_{2}^{+}}} $$1.268 \times {10^{ - 18} } \times {T_{\text{e} }^{0.71} }\times { {\text{e} }^{ - 3.4/T_{\text{e} } } }\, ({\rm m}^3{\cdot} {\rm{s} }^{-1})$3.4[41]
    26${\rm{2He^{\ast }\to e+He+He^{+}}} $4.5 × 10–16 (m3·s–1)–15[41]
    27${\rm{e+He_{2}^{+}\to He^{\ast}+He}} $$5.386\times10^{-13}\times T_{\rm e}^{-0.5}\rm (m^3{\cdot} s^{-1})$/[41]
    28${\rm{e+He^{+}\to He^{\ast}}} $$6.76\times10^{-19}\times T_{\rm e}^{-0.5}\rm (m^3{\cdot} s^{-1})$/[41]
    29${\rm{2e+He^{+}\to e+He^{\ast}}} $$6.186\times10^{-39}\times T_{\rm e}^{-4.4}\rm (m^3{\cdot} s^{-1})$/[31]
    30${\rm{e+He+He^{+}\to He+He^{\ast}}} $$6.66\times10^{-42}\times T_{\rm e}^{-2}\rm (m^6{\cdot} s^{-1})$/[31]
    31${\rm{2e+He_{2}^{+}\to He_{2}^{\ast}+e}} $1.2 × 10–33 (m6·s–1)/[31]
    32${\rm{e+He+He_{2}^{+}\to He_{2}^{\ast }+He}} $1.5 × 10–39 (m6·s–1)/[31]
    33${\rm{e+He+He_{2}^{+}\to He^{\ast }+2He}} $3.5 × 10–39 (m6·s–1)/[31]
    34${\rm{2e+He_{2}^{+}\to He^{\ast }+He+e}} $2.8 × 10–32 (m6·s–1)/[31]
    35${\rm{e+N_{2}\to e+N+N}} $$1\times10^{-16}\times T_{\rm e}^{-0.5}\times {\rm e}^{{-16}/T_{\rm{e} }}\rm (m^3{\cdot} s^{-1})$9.757[42]
    36${\rm{e+N_{2}^{+}\to N+N}} $$4.8\times10^{-13}\times T_{\rm e}^{-0.5}\rm (m^3{\cdot} s^{-1})$/[42]
    37${\rm{e+N_{2}^{+}\to N_{2}}} $$7.72\times10^{-14}\times T_{\rm e}^{-0.5}\rm (m^3{\cdot} s^{-1})$/[43]
    38${\rm{e+N_{4}^{+}\to 2N_{2}}} $$3.22\times10^{-13}\times T_{\rm e}^{-0.5}\rm (m^3{\cdot} s^{-1})$/[44]
    39${\rm{2e+N_{2}^{+}\to N_{2}+e}} $$3.165\times10^{-42}\times T_{\rm e}^{-0.8}\rm (m^6 \cdot s^{-1})$/[44]
    40${\rm{e+2O_{2}\to O_{2}+O_{2}^{-}}} $$5.17\times10^{-43}\times T_{\rm e}^{-1}\rm (m^6{\cdot} s^{-1})$–0.43[44]
    41${\rm{e+O_{2}^{+}\to O+O}} $$6\times10^{-11}\times T_{\rm e}^{-1}\rm (m^3{\cdot} s^{-1})$–6.91[44]
    42${\rm{e+O_{2}^{+}\to O_{2}}} $4 × 10–18 (m3·s–1)/[43]
    43${\rm{e+O_{4}^{+}\to 2O_{2}}} $$2.25\times10^{-13}\times T_{\rm e}^{-0.5}\rm (m^3{\cdot} s^{-1})$/[44]
    44${\rm{He^{\ast}+ 2He \to He_{2}^{\ast }+He}} $1.3 × 10–45 (m6·s–1)/[41]
    45${\rm{He^{+}+2He\to He_{2}^{+}+He}} $1 × 10–43 (m6·s–1)/[41]
    46${\rm{N_{2}+N_{2}+N_{2}^{+}\to N_{2}+N_{4}^{+}}} $5 × 10–41 (m6·s–1)/[44]
    47${\rm{O^{-}+O_{2}^{+}\to O+O_{2}}} $2 × 10–13 (m3·s–1)/[41]
    48${\rm{O_{2}^{-}+O_{2}^{+}\to O_{2}+O_{2}}} $2 × 10–13 (m3·s–1)/[41]
    49${\rm{O_{2}^{-}+O_{2}^{+}+O_{2}\to 3O_{2}}} $2 × 10–37 (m6·s–1)/[44]
    50${\rm{O_{2}^{-}+O_{4}^{+}+O_{2}\to 4O_{2}}} $2 × 10–37 (m6·s–1)/[44]
    51${\rm{O_{2}+O_{2}+O_{2}^{+}\to O_{2}+O_{4}^{+}}} $2.4 × 10–42 (m6·s–1)/[44]
    52${\rm{He^{\ast }+N_{2}\to e+He+N_{2}^{+}}} $7 × 10–17 (m3·s–1)/[41]
    53${\rm{He_{2}^{\ast }+N_{2}\to e+2He+N_{2}^{+}}} $7 × 10–17 (m3·s–1)/[41]
    54${\rm{He_{2}^{\ast }+O_{2}\to e+2He+O_{2}^{+}}} $3.6 × 10–16 (m3·s–1)/[43]
    55${\rm{He^{\ast }+O_{2}\to e+He+O_{2}^{+}}} $2.6 × 10–16 (m3·s–1)/[43]
    56${\rm{He_{2}^{+}+N_{2}\to N_{2}^{+}+2He}} $5 × 10–16 (m3·s–1)/[41]
    57${\rm{He^{+}+N_{2}\to N_{2}^{+}+He}} $5 × 10–16 (m3·s–1)/[41]
    58${\rm{He+N_{2}+N_{2}^{+}\to He+N_{4}^{+}}} $8.9 × 10–42 (m6·s–1)/[42]
    59${\rm{He+O_{2}+O_{2}^{+}\to He+O_{4}^{+}}} $5.8 × 10–43 (m6·s–1)/[42]
    60${\rm{He+O_{2}^{-}+O_{2}^{+}\to He+2O_{2}}} $2 × 10–37 (m6·s–1)/[43]
    61${\rm{O_{2}^{-}+O_{2}^{+}+N_{2}\to 2O_{2}+N_{2}}} $2 × 10–37 (m6·s–1)/[43]
    62${\rm{O_{2}^{-}+O_{4}^{+}+N_{2}\to 3O_{2}+N_{2}}} $2 × 10–37 (m6·s–1)/[44]
    63${\rm{N_{2}+O_{2}+N_{2}^{+}\to O_{2}+N_{4}^{+}}} $5 × 10–41 (m6·s–1)/[44]
    64${\rm{O_{2}+N_{4}^{+}\to 2N_{2}+O_{2}^{+}}} $2.5 × 10–16 (m3·s–1)/[44]
    65${\rm{O_{2}+N+N\to O_{2}+N_{2}}} $3.9 × 10–45 (m6·s–1)/[43]
    66${\rm{O+O+N\to O_{2}+N}} $3.2 × 10–45 (m6·s–1)/[42]
    注: f(c, ε)表示速率系数是通过电子能量分布函数(EEDF)使用相关文献中的横截面获得的. c表示He摩尔分数, ε表示平均电子能量(eV), neTe表示电子密度(m–3) 和电子温度(eV). 他代表He(23S)和He(21S). He2*代表He2(a3∑u+). N2(VIB v1), N2(VIB 3v1), N2(VIB 4v1)和N2(VIB 5v1)被视为N2, O2(VIB 3v1), O2(VIB 4v1), O2(A1), O2(B1)和O2(EXC)被视为O2; O(1D)和O(1S)被视为O.
    下载: 导出CSV

    表 3  $ \rm N_2^+, N_4^+和O_2^+ $相关的化学反应速率

    Table 3.  Reaction rates involving $ \rm N_2^+, N_4^+ \text{ and }O_2^+ $

    反应cHe = 98%轮
    廓线上
    化学反应速率
    /(mol·m–2·s–1)
    cHe = 95%轮
    廓线上
    化学反应速率
    /(mol·m–2·s–1)
    cHe = 90%轮
    廓线上
    化学反应速率
    /(mol·m–2·s–1)
    R41: e + $\rm O_2^+$ → O + O2.98 × 10–31.27 × 10–33.81 × 10–4
    R46: N2 + N2 + $\rm N_2^+ $ → N2 + $\rm N_4^+$1.67 × 10–41.61 × 10–52.67 × 10–7
    R51: O2 + O2 + $\rm O_2^+$ → O2 + $\rm O_4^+$8.86 × 10–73.83 × 10–66.70 × 10–6
    R52: He* + N2 → e + He + $\rm N_2^+ $1.29 × 10–34.48 × 10–54.96 × 10–7
    R55: He* + O2 → e + He + $\rm O_2^+$1.28 × 10–34.42 × 10–54.90 × 10–7
    R58: He + N2 + $\rm N_2^+ $ → He + $\rm N_4^+ $1.86 × 10–36.92 × 10–55.41 × 10–7
    R63: N2 + O2 + $\rm N_2^+ $ → O2 + $\rm N_4^+ $4.45 × 10–54.29 × 10–67.09 × 10–8
    R64: O2 + $\rm N_4^+ $ → 2N2 + $\rm O_2^+$1.59 × 10–39.67 × 10–41.10 × 10–4
    下载: 导出CSV
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  • 收稿日期:  2022-03-08
  • 修回日期:  2022-04-14
  • 上网日期:  2022-08-11
  • 刊出日期:  2022-08-20

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