-
用低能电子衍射研究了ⅢA-VA和ⅡB-VIA化合物(110)和(1010)表面的弛豫,发现当理论计算与实验符合得很好时其结构是:保持表面上A-B键长不变,用一个旋转角ω,使B原(离)子向外移动,A原(离)子向内移动,第一表面原子层间距d1=0.610-0.810?[对ⅢA-VA(110)],0.536—0.825?[对ⅡB-VIA(110)]和0.633-1.060?[对ⅡB-VIA(1010),第二表面原子层间距d2=1.300-1.610?[对ⅢA-VA(100)],1.430-1.700?[对ⅡB-VIA(110)]和0.820-0.930?[对ⅡB-VIA(1010),而第三表面原子层间距d3=1.410-2.440?[对ⅢA-VA(110)],2.020-2.250?[对ⅡB-VIA(110)]和1.910-2.440?[对ⅡB-VIA(1010)]。对此结构,弛豫率α是:0.24±0.02[对ⅢA-VA(110)],0.25±0.02[对ⅡB-VIA(1010)]和0.33±0.03[对ⅡB-VIA(1010)]。We have studied the relaxation of IIIA-VIA and IIB-VIA compounds AB (110) and AB (1010) surfaces with LEED, and found that the best agreement between theory and experiment occurs in such a sturcture, in which the B atoms are tilted outward and A atoms are tilted inward, with an angle of rotation ω, keeping the bond length at surface A-B unchanged, and the first atomic surfaces layer distances d1=0.610-0.810? [for IIIA-VA (110)] , 0.536-0.825?[for IIB-VIA (110)] and 0.633-1.060?[for IIB-VIA (1010)] and the second surfaces atomic layer distances d2 = 1.300-1.610?[for IIIA-VA(ll0)] , 1.430-1.700?[for IIB-VIA (110)] and 0.820-0.930?[for IIB-VIA (1010)] and third one d3 = 1.410-2.440?[for 1I1A-VA (110)], 2.020-2.250?[for IIB-VIA (110)] and 1.910-2.440?[for IIB-VIA (1010)] . For this structure the relaxation susceptibility a are: 0.24±0.02[for IIIA-VA (110)], 0.25±0.02 [for IIB-VIA (110)] and 0.33 ±0.03 [for IIB-VIA (1010)].
计量
- 文章访问数: 8008
- PDF下载量: 607
- 被引次数: 0